Python实现批量发送Post请求的脚本示例

月亮慢半拍

发布时间：2026-10-13 | 6人浏览过

原创

本文介绍如何使用Python编写脚本批量发送Post请求。通过对比Java实现，展示Python在脚本编写上的简洁与高效。代码包含随机延迟、参数构造及请求发送逻辑，适用于需要持续模拟请求的场景，如测试或数据生成。

昨天我花了一天时间学习Python。虽然我的主要编程语言是Java，也能编写一些Shell脚本，具备一定的基础，但这次想通过实际应用场景来练习Python。

这个功能我之前在Java中实现过，代码相对粗糙，且运行在本机上。今天接到任务，需要保持持续的请求发送，因此决定用Python重写。这样做不仅节省了服务器空间，避免了传输包含大量依赖项的Jar包，还使代码更清晰易读。

首先附上原始的Java代码：

package xxxxxx.base;  
import java.util.Random;  
import org.apache.commons.lang3.StringUtils;  
import haojianxiang.util.HttpRequest;  
public class CreateFeedbackData { 
 
  public static void main(String[] args) { 
    while (true) { 
      try { 
        Random r = new Random(); 
        int sleep = r.nextInt(1200000) + 600000; 
        Thread.sleep(sleep); 
        post(); 
      } catch (Exception e) { 
        e.printStackTrace(); 
      } 
    } 
  } 
   
  public static void post(){ 
    String url = "http://111.111.111.111:8080/xxxx/post"; 
     
    int[] types = {1, 2, 3, 4}; 
    int index = (int) (Math.random() * types.length); 
    int type = types[index]; 
     
//   String[] contents = {"-中文测试-，","-English Test-,","~!@#$%^&*()_;:'-\"<>?/|\\-,","     "}; 
    String[] contents = {"-中文测试-，","-English Test-,","~!@#$%,","     "}; 
     
    StringBuffer content = new StringBuffer(); 
    content.append("haojianxiang test:"); 
    for (int i = 0; i < 10; i++) { 
      int idx = (int) (Math.random() * contents.length); 
      content.append(contents[idx]); 
    } 
     
    String[] imgs = {"/Upload/appUpload/58c7b315cb39f.jpg", 
        "/Upload/appUploa/58cb467a69873.jpg", 
        "/Upload/appUpload/58afff0e99432.png", 
        "/Upload/appUpload/58b545539eb80.jpg", 
        "/Upload/appUpload/58b55d7c9e281.JPG", 
    }; 
    StringBuffer img = new StringBuffer(); 
     
    for (int i = 0; i < (int) (Math.random() * 4); i++) { 
      int lucky = (int) (Math.random() * 2); 
      if (lucky == 1) { 
        int idx = (int) (Math.random() * imgs.length); 
        img.append(imgs[idx]); 
        img.append(","); 
      } 
    } 
    String imgStr = ""; 
    if (StringUtils.isNotBlank(img)) { 
      imgStr = img.substring(0, img.length()-1); 
    } 
    String param = "{\"req\":{\"userId\":xxxxxx}," + 
        "\"data\":{"\"fbType\":" + type + ",\"fbContent\":\""+content.toString()+ 
        "\",\"fbPic\":\""+imgStr+"\"}}"; 
    String rst = HttpRequest.sendPost(url, param); 
    System.out.println("TIME--"+ System.currentTimeMillis() + " result:" + rst); 
  } 
 
}

（代码中的参数地址已做隐藏处理，JSON格式可能不完全准确，但这不影响示例的核心逻辑）

接下来是Python版本的代码：

#!/usr/bin/env python 
# -*- coding: utf-8 -*- 
 
import random 
import urllib 
import urllib.request 
import time 
 
def postFeedBack(): 
  url = "http://111.111.111.111:8080/xxxx/post" 
 
  type = int(random.uniform(1,5)) 
  contents = ["-中文测试-，","-English Test-,","~!@#$%,","   "] 
  content = "haojianxiang test:" 
  for i in range(0,10): 
    content += random.choice(contents) 
 
  img = "" 
  imgs = ["/Upload/58c7b315cb39f.jpg", 
      "/Upload/58cb467a69873.jpg", 
      "/Upload/58afff0e99432.png", 
      "/Upload/58b545539eb80.jpg", 
      "/Upload/58b55d7c9e281.JPG"] 
  for i in range(0,3): 
    lucky = int(random.uniform(0,2)) 
    if lucky == 1: 
      img += random.choice(imgs) 
      img += "," 
  img = img[:-1] 
  data = "{\"req\":{\"userId\": xxx}," 
  data += "\"data\":{ 
  data += "\"fbType\":" 
  data += str(type) 
  data += ",\"fbContent\":\"" 
  data += content 
  data += "\",\"fbPic\":\"" 
  data += img 
  data += "\"}}" 
 
  pdata = bytes(data,encoding="utf-8") 
  f = urllib.request.urlopen(url,pdata) 
 
  result = f.read() 
  result = result.decode('UTF-8') 
  print(result) 
 
if __name__ == "__main__": 
  while True: 
    st = int(random.uniform(600,1800)) 
    print("sleep:",st) 
    time.sleep(st) 
    postFeedBack()

Python的写法确实更加简洁高效。在Java代码中，Post请求的逻辑还调用了自定义的工具类，实际代码量会更大。今后我计划将Python作为首选的脚本语言，因为它处理简单问题非常迅速。