Python统计字符串中英文字母、数字、空格及其他字符数量的实现方法

# -*- coding: utf-8 -*-
# 要求：输入一行字符，分别统计出其中英文字母、空格、数字和其它字符的个数。
def count(s):
 count_a=count_z=count_o=count_s=0
 for i in s:
  if (ord(i)>=97 and ord(i)<=122) or (ord(i)>=65 and ord(i)<=90):
   count_a=count_a+1
  elif ord(i)>=48 and ord(i)<=57:
   count_z=count_z+1
  elif ord(i)==32:
   count_s=count_s+1
  else:
   count_o=count_o+1
 print "英文字母个数：%d个"%count_a
 print "数字个数：%d个"%count_z
 print "其他字符个数：%d个"%count_o
 print "空格个数：%d个"%count_s
 
 
if __name__=="__main__":
 s=raw_input("请输入一串字符：")
 count(s)